This has been going around, and someone asked for help with it, so I've laid out my thought process to solve this below:
Clue 1) 682 - one digit is right and in its place
So it's 6??, ?8? or ??2
Only 6, 8 or 2 can be in the number (assumption: "one" here means "one and only one" - similar assumption applies below)
Clue 2) 614 - one digit is right but in the wrong place
So the full number contains either 6, 1 or 4 but not the other 2
With 1) we know it can't be 6
Possible numbers: 0, 1, 2, 3, 4, 5, 7, 8, 9
Clue 3) 206 - two digits are right but both are in the wrong place
We know it cannot be 6. So the number contains 2 and 0
Possible numbers: 0, 1, 2, 3, 4, 5, 7, 8, 9
Definite numbers: 0, 2
Clue 4) 738 - all digits are wrong
Possible numbers: 0, 1, 2, 4, 5, 9
Definite numbers: 0, 2
From 1), we know it ends with 2
So the number is ??2
From 3) we know the middle number cannot be 0
So the number is 0?2
Possible numbers to fill the gap: 1, 4, 5, 9
From 2) we know it's 1 or 4 but also that the centre number cannot be 1
So it's 042
Clue 5) 380 - one digit is right but in the wrong place
This seems unnecessary